(x-1)^2/3=(16x-79)^1/3

Solution for (x-1)^2/3=(16x-79)^1/3 equation:

x in (-oo:+oo)

((x-1)^2)/3 = ((16*x-79)^1)/3 // - ((16*x-79)^1)/3

((x-1)^2)/3-(((16*x-79)^1)/3) = 0

((x-1)^2)/3-((16*x-79)/3) = 0

((x-1)^2)/3+(-1*(16*x-79))/3 = 0

(x-1)^2-1*(16*x-79) = 0

x^2-18*x+80 = 0

x^2-18*x+80 = 0

x^2-18*x+80 = 0

DELTA = (-18)^2-(1*4*80)

DELTA = 4

DELTA > 0

x = (4^(1/2)+18)/(1*2) or x = (18-4^(1/2))/(1*2)

x = 10 or x = 8

(x-8)*(x-10) = 0

((x-8)*(x-10))/3 = 0

((x-8)*(x-10))/3 = 0 // * 3

(x-8)*(x-10) = 0

( x-10 )

x-10 = 0 // + 10

x = 10

( x-8 )

x-8 = 0 // + 8

x = 8

x in { 10, 8 }